PETIN M.I.

       The World PETIN - METON calendar

 

    Contents  http://NewWorldCalendar.narod.ru/index.htm        

 

Examples I - IV.  The passing  from the World Petin-Meton calendar

                          (Gregorian part) to existing  the Gregorian calendar.

 

      The  examples of calculation  of the World Petin-Meton calendar (Gregorian part) -  102,  2004  AD  etc

         is considered below.

I. Example.  The passing  from the World Petin-Meton calendar (Gregorian part)

                       to existing  the Gregorian calendar

       1.  102 11 = 91 days ,   as  date 102 > data 11, which is  December, 31 in the preceding year.

       

  Note.  If  date  <  11,  for example date of the World PETIN-METON calendar is  9,  2004  AD,

                       its necessary to make correction:

                    1A.            2004     years

                            -    1   

                        -----------

                           2003 years ,  and then

         2A.      9 11 + 365 =363  days,  (see table 1 column Simple - http://Petin20Mikhail.narod.ru/index.htm  )

         3A.      363

                   334  ,   where:  334  is mod Mi  for [1+...+11] months  (table 1).

               -------------

                        29 days,  i.e.  December 29.

        4A.      Finally,  date 9, 2004  AD  [the World Petin-Meton calendar (Gregorian part)] is December 29, 2003 AD                     (existing  the Gregorian calendar)

 

  

NoteLeapG is a Gregorian leap year, i.e. +1 day.

           LeapM is a Meton leap year, i.e. -1 day.

 

          The rule of definition of simple solar years

          at which the duration of each year is equal to 365 days, but years:

) multiple of            4, are equal to 365+1 = 366 days,  i.e.  leapG years;

) multiple of        100, are equal to 365 days;

) multiple of        400, are equal to 365+1 = 366 days,  i.e.  leapG years;

) multiple of      3200, are equal to 365 days;

) multiple of 134 400, are equal to 365+1 = 366 days,   i.e.  leapG years.

                                                                                  

       2.    As  2004  is a leapG year  and 102 > 59,    therefore

             

       3.     92 91 = 1 April,  here  91 is modMg  for [1+2+3] months  (table 1).

               Finally, date 102, 2004 AD [the World Petin-Meton calendar (Gregorian part)] is April 1,  2004  AD, 

               LeapG  year.              

 

II.  The definition of  JD.  Date 1 of April,  2004

      4.   2004 year

               1,  i.e.     the correction between  BC/AD

        ---------

            2003 year

      5.   2003 : K1 = 5,0075,    where:   K1 = 400 from the table 2 -(  http://Petin20Mikhail.narod.ru/index.htm )

                                                       for interval of (>400) 2800 years.

         We take  5 instead of   5,0075

                     5 x K1 = 5 x 400 = 2000 years

                     5 x K2  = 730 485  days,   where:  K2 = 146 097 from the table 2

                                                                          for interval of (>400) 2800 years.

       6.  2003 2000 =3 years

       7.   3 : K1 = 1 ,   where:   K1 = 3  from the table 2

                                         for interval of (>3) 4 years.

              1 x K1 =3 years

              1 x K2 = 1095  days,   where:  K2 = 1095 from the table 2

                                                        for interval of (>3) 4 years.

       8.   For leapG  year  and the [1+2+3] months  (before April, see table 1) modMg = 91 days.

       9.   The sum of days:

             730 485

                  1095

                      91                       

          --------------------      

            731 671 days

     10.  Finally,  JD for  April 1, 2004

              731 671

           1 721 426    i.e.  JD of   January 01, 1 AD                    

        ------------------

         2 453 097 days   i.e.  April 1,  2004   it coincides with a result of the working algorithm for Forsythes   

             converter:  http://home.austin.rr.com/rumblefische/calendars/cconverter.html               

             

III.   Return  account

        1.    2 453 097 days ,  i. e.  JD  of  a solar date X   (the sum)     

    - 1 721 426,  i.e.  JD  of   January  01, 1 AD        ( the augend)

       -------------

         731 671  days    ...(the addend) , i.e. interval (JD) between January 01, 1 AD and a solar date X.

                                                                      

2.   731 671 : K2 =5, 0081,     where:  K2 = 146 097 from the table 2  -  ( http://Petin20Mikhail.narod.ru/index.htm )

                                                              for interval  of 146 098 1 022 679 days.

We take  5 instead of   5,0081

                    5 x K1 = 5 x 400 = 2000 years,  where:  K1 = 400 from table 2   for interval  of 146 098 1 022 679 days.

                    5 x K2  = 730 485  days,   where:  K2 = 146 097 from the table 2

3.        731 671

         - 730 485 

          ----------------

               1186 days interval with leapG year (table 2), i.e. JD between January 01, 2001 AD and a solar date X.

4.   1186 : K2 = 1,084,  ,     where:  K2 = 1095 from the table 2

                                                         for interval  of 1096 1 461 days.

           We take  1 instead of   1,084 and

                    1 x K1 = 1 x 3 = 3 years,   where:  K1 = 3  from the table 2  for interval  of 1096 1 461 days.

                    1 x K2  = 1095  days,   where:  K2 = 1095  from the table 2.

5.      1186 days

       - 1095

       --------------

             91 days  in the leapG year  (the augend), i.e. JD between January 01, 2004 AD and a solar date X.

                           

6.    It is necessary to define a quantity of months and days between  January 01, 2004 AD and a solar date X.

       In leapG  year  a nearest mini modMg (table 1) is 91 days, i.e.  the [1+2+3] months and 00 days.

 

7.            January  01,  2004  AD

      +    3 months  00                        

          --------------------------------

                   April  01,  2004  AD

8 .   The sum

                     1   i.e. .  the correction between  BC/AD

      +       2000 years

                     3 years

             -------------------

              2004 years   ,  i.e.   finally   April  1,  2004 (existing Gregorian calendar)

 

 

          IV. Example The passing  from existing  the Gregorian calendar

                     to the World PETIN-METON calendar (Gregorian part).

It is necessary to make the following:   

6A.   After  mentioned above point 5 Example III

                          92 days

                       + 11 days

                     ----------------

                        103 days   

Notes: a) if the given result is equal to 71 in the leapG year this is date 366 in the World PETIN-METON  

                  calendar.

             b) if the result is equal to < 71 in any year, point 7A mentioned below no required

             c) any result in the simple year  doesn't require  point 7A.

7A.   As  two conditions (leapG year and  103 > 71) are simultaneously

                        103 days

                       -    1 day     i.e.  leapG day  

                     -----------------

                        102 days,    i.e.  finally   102,   2004 (Gregorian part of the World PETIN-METON calendar)

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     Contents  http://NewWorldCalendar.narod.ru/index.htm                

 

 



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